Tom Brady will have one of his favourite targets with him again next season as the Tampa Bay Buccaneers defend their Super Bowl championship.
Tight end Rob Gronkowski agreed to a one-year deal to play another season in Tampa Bay, his agent Drew Rosenhaus told NFL Network and ESPN last night.
The Athletic and NFL Network reported that the contract will pay Gronkowski $8million and includes the opportunity to earn another $2m in incentives.
Gronkowski tweeted a gif of Patchy the Pirate from SpongeBob SquarePants saying, "Arrr You Ready Kids?!?"
https://t.co/GMzEde379q pic.twitter.com/Sg3RWYplQm— Rob Gronkowski (@RobGronkowski) March 15, 2021
Gronkowski, 31, came out of retirement before the 2020 season to reunite with his former New England Patriots quarterback, Brady, in Tampa Bay.
TheBuccaneers' title last month gave Brady a record seven Super Bowl titles while Gronkowski won his fourth.
A four-time All-Pro, Gronkowski produced mediocre numbers by his standards in the 2020 regular season: 45 catches for 623 yards and seven touchdowns.
In the Buccaneers' first three playoff games, he totalled just two catches for 43yards, but he was a key contributor in the Super Bowl against the Kansas City Chiefs, making six receptions for 67 yards and two TDs.
The Brady-Gronkowski connection has accounted for 14 career pla-yoff touchdowns, the top figure for any quarterback/pass-catcher duo in league history.
Gronkowski, selected by New England in the second round of the 2010 draft out of Arizona, played for the Patriots from 2010-18, compiling 521 catches for7,861 yards and 79 touchdowns. He topped the 1,000-yard receiving mark four times.